Question:
(12) Find the probability that in an arrangement of the letters of the word
“DAUGHTER†the letter D occupies the first place.
Answer:
The word DAUGHTER contains 8 letters and all are different.
So, total number of arrangement = 8! = 40320
Let A be the event of getting a word with D at the first place.
So, favorable cases to the event A = 1 * number of ways of arranging 7 letters (except D)
= 1*7! = 6040
Now, P(D occupies first place) = 5040/40320 = 1/8
Not what you are looking for? Go ahead and submit the question, we will get back to you.
